r^2=24.96

Solution for r^2=24.96 equation:

r^2=24.96

We move all terms to the left:

r^2-(24.96)=0

We add all the numbers together, and all the variables

r^2-24.96=0

a = 1; b = 0; c = -24.96;
Δ = b2-4ac
Δ = 02-4·1·(-24.96)
Δ = 99.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{99.84}}{2*1}=\frac{0-\sqrt{99.84}}{2}
=-\frac{\sqrt{}}{2}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{99.84}}{2*1}=\frac{0+\sqrt{99.84}}{2}
=\frac{\sqrt{}}{2}
$